# 20. lim_{x to infinty}{1+5e^(ax)}/{7+2e^(ax)} where a<0 is constant.

## Question:

{eq}20. \lim\limits_{x\to+\infty} \frac{1+5e^{ax}}{7+2e^{ax}} {/eq} where a<0 is a constant.

## Limits:

In order to find the value of the given function, we will first simplify the given function. Thereafter, we will solve it to get the required answer. Here we need to keep in mind that, any value divided by infinity is always equal to zero.

## Answer and Explanation: 1

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{eq}\begin{align*} \ & \lim\limits_{x\to+\infty} \frac{1+5e^{ax}}{7+2e^{ax}} \end{align*} {/eq} where a<0 is a constant.

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Chapter 6 / Lesson 4A limit can tell us the value that a function approaches as that function's inputs get closer and closer to a number. Learn more about how to determine the limits of functions, properties of limits and read examples.